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7 April, 00:52

What is the discrimination of 3x^2+6x=2

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  1. 7 April, 04:05
    0
    60

    D>0, there are 2 distinct real roots

    Explanation:

    3x2+6x-2=0

    a=3, b=6, c=-2

    The formula for discriminant is b2-4acSubstitute the given values.

    b2-4ac

    (6) 2-4 (3) (-2)

    =60

    therefore, D>0, there are 2 distinct real roots
  2. 7 April, 04:35
    0
    Discriminant, not discrimination. I'm not discriminating against you.; )

    You must re-write 3x^2+6x=2 in standard form: 3x^2 + 6x - 2

    Here a=3, b=6 and c = - 2

    The discriminant is b^2 - 4ac. Here, it's 6^2 - 4 (3) (-2), or 36 + 24, or 60.

    This quadratic has two real, unequal, zeros.
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