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24 December, 17:20

What is the true solution on 2 in e ^in 5x=2 in 15

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  1. 24 December, 20:56
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    2In (e^ (In5x)) = 2 ln15

    In (e^x) = x

    2 (ln5x) = 2ln15

    In 5x=In 15

    5x = 15

    x = 3

    genius
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