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28 May, 01:08

In a set of integers between 18 and 95, inclusive, how many are divisible by 6 but not 12?

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Answers (2)
  1. 28 May, 03:33
    0
    18≤12n≤95 divide all term by 12

    1.5≤n≤7.9

    n=[2,7]

    So multiples of 12 are 7-2+1=6

    18≤6n≤95 divide all terms by 6

    3≤n≤15.8

    3≤n≤15

    So multiples of 6 are 15-3+1=13

    So there are 13-6=7 multiples of 6 that are not multiples of 12 in the set of integers [18,95]
  2. 28 May, 04:14
    0
    18≤12n≤95 divide all term by 12

    1.5≤n≤7.9

    n=[2,7]

    So multiples of 12 are 7-2+1=6

    18≤6n≤95 divide all terms by 6

    3≤n≤15.8

    3≤n≤15

    So multiples of 6 are 15-3+1=13

    So there are 13-6=7 multiples of 6 that are not multiples of 12 in the set of integers [18,95]
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