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2 January, 16:35

Find a normal vector n to the plane z - 2 (x - 8) = 3 (7 - y)

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  1. 2 January, 17:37
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    Consider this option:

    1) z-2 (x-8) = 3 (7-y) ⇔ - 2x+3y+z-5=0 (common view is Ax+By+Cz+D=0);

    2) for normal vector n (A; B; C) = n (-2; 3; 1).

    Answer: n (-2; 3; 1)
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