Ask Question
4 July, 16:25

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.

A. 11 L

B. 15 L

C. 25 L

+4
Answers (1)
  1. 4 July, 19:22
    0
    The answer is B

    15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution. A. 11 L B. 15 L C. 25 L ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers