2x-5y=10; what is the x intercept, what is the y intercept, what is the slope?

First we put the equation in y = mx + b form where m is ur slope and b is ur y int.

2x - 5y = 10

-5y = - 2x + 10

y = 2/5x - 2 ... so ur slope is 2/5 and ur y int is (0,-2) <==

to find ur x int, sub in 0 for y and solve for x

2x - 5y = 10

2x - 5 (0) = 10

2x = 10

x = 10/2

x = 5 ... and ur x int is (5,0) <==

another way to find the y int is to sub in 0 for x and solve for y ... but u might as well solve it by putting it in y = mx + b form because that way u have ur slope as well.

2x-5y=10

subtract 2x on both side of the equal sign and you're left with

-5y=-2x+10

then you divide everything by - 5 to get

y = 2/5x-2

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X - intercept = (5,0)

y = - 2

slope = 2/5x

Hope that makes some kind of sense!