Michelle has 5coins worth 75 cents what coins did she have?

One possibilities there is that there is:

2 quarters

2 dimes

1 nickel

25 + 25 + 10 + 10 + 5 = 75

We need to divide the total cents by the amount of coins so that we know how much each coin is worth:

75/5 = 15

but there aren't coins worth 15 cents.

So lets accomodate the total in known coins:

1 cent, 5 cents, 10 cents, 25 cents, 50 cents.

take this combination:

2 (25) + 2 (10) + 1 (5) = 50 + 20 + 5 = 75

so she could have 2 coins of 25 cents, and 2 coins of 10 cents, and 1 coin of 5 cents