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Edgar Ayers
6 March, 00:48
Integral of (3x-2) / (x-1) ^2
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Edgar Ward
6 March, 02:17
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(3x-2) / (x-1) ^2 = A / (x-1) + B/x (x-1) ^2
=[ A (x-1) + Bx (x-1) ] / 2 3x-2=A (x-1) + Bx
3x-2=x (A+B) - A
A+B=3
-A=-2=>A=2
A+B=3=>2+B=3=>B=1
lets check our partial fraction we have 2 / (x-1) + x / (x-1) ^2 = [ 2 (x-1) + x] / (x-1) ^2
= (3x-2) / (x-1) ^2
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