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30 March, 07:04

What equation of a line is perpendicular to 6x+4y=3?

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  1. 30 March, 08:27
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    First find the slope of the given line. 6x+4y=3. Isolate y. 4y=-6x+3, y=-3/2x+3/4.

    The slope is - 3/2. A perpendicular slope would equal the negative reciprocal of - 3/2, which is 2/3.

    The answer would be any line with a slope of 2/3 (ie y=2/3x-1).

    To check, graph the given and derived equation.
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