Find an equation of the circle that has center, 1-1 and passes through, 32

hello:

an equation of the circle Center at the A (a, b) and ridus : r is:

(x-a) ² + (y-b) ² = r²

in this exercice : a = 1 and b = - 1 (Center at A (1, - 1)

r = AP

r² = (AP) ² ... P (3,2)

r² = (3-1) ² + (2+1) ² = 4+9=13

an equation of the circle that satisfies the stated conditions.

Center at A (1, - 1), passing through P (3, 2) is : (x-1) ² + (y+1) ² = 13²