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19 August, 04:06

The equation x2+px-35=0 has one root that is equal to 7. Find the other root and the value of the coefficient p.

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  1. 19 August, 05:56
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    For this case we have the following polynomial:

    x2 + px-35 = 0

    We can factor the polynomial.

    Rewriting we have:

    (x-7) * (x + a) = 0

    The value of a is given by:

    -7 * a = - 35

    a = 35/7

    a = 5

    Substituting we have:

    (x-7) * (x + 5) = 0

    Therefore, the value of p is:

    p = - 7 + 5

    p = - 2

    Answer:

    the other root is:

    x = - 5

    The value of the coefficient is:

    p = - 2
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