The area of a triangular flag is 4242 square centimeters. its altitude is 2 centimeters longer than twice its base. find the lengths of the altitude and the base.

A = (h * b) / 2

h = 2b + 2

A = 42

42 = (b (2b + 2)) / 2

42 = (2b^2 + 2b) / 2

42 = b^2 + b

b^2 + b - 42 = 0

(b + 7) (b - 6) = 0

b + 7 = 0

b = - 7 ... nope ... extraneous solution

b - 6 = 0

b = 6 < = = base

h = 2b + 2

h = 2 (6) + 2

h = 12 + 2

h = 14 < = = = height (altitude)