Ask Question
28 January, 22:08

A local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimensions of the court. write the equation out then solve.

+3
Answers (1)
  1. 29 January, 01:36
    0
    50x20=1000

    1000x (1/4) = 250

    1000-250=750ft^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimensions of the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers