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Mathematics
Liliana
9 June, 07:41
How do you solve 2ln (2x+5) = 8?
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Aniyah Fernandez
9 June, 09:15
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Well you have to use one of the logarithm laws
b * ln (x) = ln (x^b)
So
2 ln (2x + 5) = 8
ln [ (2x+5) ^2] = 8
So now if we do e^x on both sides and we say that x is going to be what either side equals like this
e^ (ln [ (2x+5) ^2]) = e^8
We we know that
e^[ln (x) ] = x so
[ (2x+5) ^2] = e^8
take square root of both sides
2x + 5 = e^4. and - (2x+5) = e^4
2x = e^4 - 5. and - 2x = e^4 + 5
x = (e^4 - 5) / 2 and x = (e^4 + 5) / - 2
now just use a calculator to solve
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