The sum of three consecutive integers is 114. Find the integers

Let the first number be x, the second number be x+1, and the third number be x+2.

x + x+1 + x+2 = 114

3x + 3 = 114

3x = 111

x = 37

x+1 = 38

x+2 = 39

So, the three consecutive numbers are 37, 38, and 39.

Consecutive integers are represented by

first number=x

second=x+1

third=x+2

so x+x+1+x+2=114

solve

3x+3=114

subtract 3

3x=111

divide 3

37=x

the numbers are

37,38,39