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4 December, 23:56

F (x + 2) is a factor of x3 - 6x2 + kx + 10, k =

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  1. 5 December, 02:55
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    X+2 is a factor of given polynomial So x=-2 is a zero of that polynomial Now Put the value of x in polynomial X3-6x2+kx+10=0 (-2) ^3-6 * (-2) ^2-k*2+10=0 Or - 8-24-2k+10=0 Or - 32+10=2k Or - 22=2k So K=-11
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