A regular octagon has sides measuring about 4cm. If the octagon is divided into 8 congruent triangles, each has a height of 5 cm. What is the area of the octagon?

Question

Mathematics

Ralph

16 February, 16:16

A regular octagon has sides measuring about 4cm. If the octagon is divided into 8 congruent triangles, each has a height of 5 cm. What is the area of the octagon?

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Answers (2)

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Koen Joyce · Answer 1

Base of each triangle = about 4 cm

Height of each triangle = 5 cm

Area of each triangle = (1/2) (base) (height)

and there are 8 of them.

Total area = (8) x (1/2) x (base) x (height) =

(4) x (about 4 cm) x (5 cm) = about 80 cm².

James Stone · Answer 2

The area of a triangle is 1/2*base*height

So, do that for one of the triangles, since they're all the same 1/2*4*5=10cm squared

Multiply by 8 to find the total

10*8=80

80 cm squared.