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13 September, 20:41

The vertex of the function's graph is given. Find c. y = - 3x2 + 6x + c; (1, 0)

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  1. 13 September, 23:28
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    Vertex form of a parabola is:

    y = a (x - h) ^2 + k

    Where vertex (h, k) is given to be (1,0) and x terms are factorable by "a" = - 3

    y = - 3 (x-1) ^2 + 0

    expand the parenthesis

    y = - 3 (x-1) (x-1)

    y = - 3 (x^2 - x - x + 1)

    multiply - 3 through parenthesis

    y = - 3x^2 + 6x - 3

    Compare to given equation

    c = - 3
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