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14 January, 13:23

Given the function f (x) = - 3e^x^+^1, find f (x) if x=2

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  1. 14 January, 14:38
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    F (x) = - 3e^ (x + 1)

    f (2) = - 3e^ (2 + 1) = - 3e^3
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