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26 September, 04:20

Evaluate ∫ cot 2x dx. A. 1⁄2 Ln csc 2x + C B. 1⁄2 Ln cos 2x + C C. 1⁄2 Ln sin 2x + C D. 1⁄2 Ln sec 2x + C

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  1. 26 September, 07:50
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    Cot (2x) dx = [cos (2x) / sin (2x) ] dx, and note that the derivative of sin (2x) = 2cos (2x) dx, which is double of the numerator.

    Therefore, this can be integrated using an ln function of sin. This results in:

    (1/2) ln (sin2x) + C

    This is choice C.
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