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4 November, 04:36

Find the center and radius of the circle x2 + y2 - 16x = 0

Answers (2)
  1. C
    4 November, 06:32
    0
    The answer is (8)

    Move all variables to the left side and all constants to the right side. x2 + y2 - 16x=0

    Complete the square for x2 - 16x

    (x-8) 2 - 64

    Substitute (x-8) 2 - 64 for x2 - 16x in the equation

    x2 + y2 - 16x=0 x2 + y2 - 16x=0 - (x-8) 2-64+y2=0

    Move - 64 to the right side of the equation by adding 64 to both sides.

    (x-8) 2 + y2 = 0+64

    Add 0 and 64 to get 64.

    (x-8) 2 + y2 = 64

    This is the form of a circle. Use this form to determine the center and radius of the circle.

    (x-h) 2 + (y-k) 2 = r2

    Match the values in this circle to those of the standard form. The variable r represents the radius of the circle, h represents the x-offset from the origin, and k represents the y-offset from origin.

    r=8 h=8 k=0

    The center of the circle is found at (h, k). Center: (8,0)

    These values represent the important values for graphing and analyzing a circle. Center: (8,0) Radius: 8
  2. D
    4 November, 07:08
    0
    y = √ - x2 + 16x or y = - √ - x2 + 16x
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