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20 September, 14:14

1. Derive the quadratic formula from the standard form (ax2 + bx + c = 0) of a quadratic equation by following the steps below.

2. Divide all terms in the equation by a.

3. Subtract the constant (the term without an x) from both sides.

4. Add a constant (in terms of a and b) that will complete the square.

5. Take the square root of both sides of the equation.

6. Solve for x.

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  1. 20 September, 15:38
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    We are given that:

    a x^2 + b x + c = 0

    Divide all terms with c / a:

    x^2 + (b / a) x + (c / a) = 0

    Subtract c from both sides:

    x^2 + (b / a) x + (c / a) - c / a = 0 - c / a

    x^2 + (b / a) x = - c / a

    Add a constant k to complete the square:

    where k = ((b / a) / 2) ^2 = (b / 2a) ^2

    x^2 + (b / a) x + k = - c / a + k

    x^2 + (b / a) x + (b/2a) ^2 = - c / a + (b / 2a) ^2

    So the perfect square trinomial is:

    (x + b/2a) ^2 = - c / a + (b / 2a) ^2

    Taking the square root of both sides:

    x + b/2a = sqrt [ - c / a + (b / 2a) ^2]

    x = sqrt [ (-c/a) + (b / 2a) ^2] - (b/2a)
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