Y for a daily lottery, a person selects a three-digit number. if the person plays for $1, she can win $500. find the expectation. in the same daily lottery, if a person boxes a number, she will win $80. find the expectation if the number 123 is played for $1 and boxed. (when a number is "boxed," it can win when the digits occur in any order.)

The expected value of the first game is - $0.50 and of the second game is - $0.52.

There are 10³ possible numbers for the lottery, and only 1 of them will match in the correct order; this gives a probability of 1/1000. To find the expected value, we multiply this by the winnings (499 after the $1 cost); we also multiply the probability of losing (999/1000) by the amount lost (-1):

1/1000 (499) + 999/1000 (-1)

499/1000 - 999/1000 = - 500/1000 = - 0.50

For the second game, since the number is "boxed", there are 3! ways to get the correct digits; this gives a probability of 6/1000. Multiply this by the winnings, 79 (after the $1 cost); multiply the probability of losing (994/1000) by the loss (-1):

6/1000 (79) + 994/1000 (-1) = 474/1000 - 994/1000 = - 520/1000 = - 0.52