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22 October, 23:07

How many zero pairs must be added to the function f (x) = x2 - 6x + 1 in order to begin writing the function in vertex form?

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Answers (2)
  1. 23 October, 01:46
    0
    Hello:

    x²-6x+1 = x²-2 (3) (x) + 3²-3²+1

    = (x-3) ²-8 ... (. vertex form)
  2. 23 October, 02:21
    0
    There must be added one zero pair: - 9, 9.

    f (x) = x² - 6 x + 9 - 9 + 1 = (x² - 6 x + 9) - 8 =

    = (x - 3) ² - 8 (the vertex form)
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