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17 August, 14:32

The length of a rectangle is 2 yd longer than its width. if the perimeter of the rectangle is 40 yd, find its area.

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  1. 17 August, 16:54
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    perimeter = 2L+2W

    L=2+w

    40 = 2L+2W

    40 = 2 (2+w) + 2W

    40=4+2w+2w

    36=4w

    w=9

    L=9+2=11

    2 (9) = 18, 2 (11) = 22, 22+18 = 40

    L=11

    W=9

    Area = L x w

    area = 11x9 = 99 square yards
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