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21 July, 15:50

A man in a lighthouse tower that is 30ft he sports a ship at sea at an angle of depression of 10 degree how far is the ship from the base of the lighthouse

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  1. 21 July, 16:57
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    We have a triangle where.

    a=adjacent leg of A=30 ft

    A=90º - (angle of depression) = 90º-10º=80º

    b=distance between the base of the lighthouse and the ship

    tan A = opposite / adjacent.

    tan 80º=b / 30 ft ⇒b = (30 ft) (tan 80º) ≈170.14 ft

    Answer: the distance would be 170.14 ft
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