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28 April, 04:58

If sin theta = 1/4 and theta is in quadrant ii, find the exact value of sin (theta-pi/3)

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  1. 28 April, 08:37
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    To get the value required we proceed as follow:

    sin θ=1/4

    θ = arcsin 1/4

    θ=14.4775~14.5°

    Since it is in the quadrant ii, the value of θ=180-14.5=165.5°

    Answer: 165.5°
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