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16 April, 12:28

If the area is 72 and the perimeter is 34, what are it's dimensions

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  1. 16 April, 15:42
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    Xy = 72

    2x + 2y = 34 (Im assuming uts a rectangle or square)

    2 (72/y) + 2y = 34

    144 + 2y^2 = 34y

    2y^2 - 34y + 144 = 0

    y = 9 or 8

    So the length is 9 and width = 8
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