Compare f (x) = 4 (x+3) ^2-6 to the parent f (x) = * ^2 and then state the vertex.

In form

y=a (x-h) ²+k

vertex is (h, k)

f (x) = 4 (x - (-3)) ² + (-6)

vertex is (-3,-6)

parent is

f (x) = 1 (x-0) ²+0

vertex is (0,0)

the other one is 3 to the left and 6 down from parent function