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2 February, 16:49

Solve for x x2+4x-21=0

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Answers (2)
  1. 2 February, 19:55
    0
    If I did my math correctly it would be that x=2.04
  2. 2 February, 20:08
    0
    First you calculate the determinant:

    d=b^2-4ac

    d=4^2-4*1 * (-21) = 16+84=100

    Because d>0 there are two solutions for x:

    x_1 = (-b+√d) / 2a = (-4+√100) / 2*1 = 6/2 = 3

    x_2 = (-b-√d) / 2a = (-4-√100) / 2*1 = - 14/2 = - 7

    The solutions for x is x = 3 and x = - 7
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