if a cylindrical bar has radius 2m and height 9cm and if it is melted and become a sphere. what is the radius of the sphere?

Volume of the Cylindrical bar, V = pi * r^2 * h

V = pi * 200^2 * 9

V = 22/7 * 40000 * 9

Let's assume the radius of the sphere as r

Volume of the sphere V1 = 4/3 * pi * r^3

V1 = V

V1 = 4/3 * pi * r^3

22/7 * 40000 * 9 = 4/3 * 22/7 * r^3

r^3 = (40000 * 9) * 3/4

r^3 = 10000 * 9 * 3

r = (10 * 10^3 * 3^3) ^ (1/3)

r = 10^ (1/3) * 10 * 3

r = 2.154 * 30

r = 64.63 cm