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17 June, 02:12

What is the sum of the first 14 terms of the sequence : an=6n-12

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  1. 17 June, 03:02
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    A1=6*1-12=-6 arithmetic sequence

    a14=6*14-12=72

    sum = n (a (1) + a (n)) / 2

    sum = 14 * (-6+72) / 2=462
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