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7 October, 23:09

A gymnast dismounts the uneven parallel bars. Her height, h, depends on the time, t, that she is in the air h = - 162 + 24t + 16. How long will it take the gymnast to reach the ground?

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  1. 8 October, 02:15
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    That is when h=0

    so assuming yo meant

    h (t) = - 16t²+24t+16

    solve for t such that h (t) = 0

    because when height=0, the gymnast hits the ground

    so

    0=-16t²+24t+16

    using math (imma complete the square

    0=-16 (t²-3/2t) + 16

    0=-16 (t²-3/2t+9/16-9/16) + 16

    0=-16 ((t-3/4) ²-9/16) + 16

    0=-16 (t-3/4) ²+9+16

    0=-16 (t-3/4) ²+25

    -25=-16 (t-3/4) ²

    25/16 = (t-3/4) ²

    sqrt both sides

    +/-5/4=t-3/4

    3/4+/-5/4=t

    if we do plus (because minus would give us negative height)

    8/4=t

    2=t

    it takes 2 seconds
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