The sum of 4 consecutive multiples of 8 is 208. What is the largest number in the set?

X will be the smallest number in the set. Let's make an equation for the second smallest, third smallest, and largest.

x+8 = second smallest

x+16 = third smallest

x+24 = biggest

Let's add them.

x+x+8+x+16+x+24=208; let's add like terms.

4x+48=208; let's subtract 48 from both sides.

4x=160; let's divide.

160:4=40

This means the smallest number is 40. We can now check our answer.

40+48+56+64

88+120

208

So, the biggest number is 208.

The largest number is 64.