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26 November, 08:52

Find the sum of the first five terms of a geometric series with a1 = 0.28, a5 = 362.88 and r = 6

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  1. 26 November, 11:57
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    The sum of a geometric series is given by:

    Sn=[a (r^n-1] / (r-1)

    the nth term is given by

    an=ar^ (n-1)

    From the information given:

    a1=0.28, r=6

    the sum of the first 5 terms will be:

    s₅=[0.28 (6^5-1) ] / (6-1)

    s₅=[0.28 (7776-1) ]/5

    s₅=2177/5

    s₅=435.4
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