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10 November, 14:23

Solve 2x - 1 < 7 and 5x + 3 < 3. x < 0 x 0 < x < 4

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  1. 10 November, 15:12
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    2x - 1 <7; then, 2x < 8; then x < 4;

    5x + 3 < 3; then, 5x < 0; then x < 0;

    Finally, {x / x < 0};
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