5y^2 - 2y - 7 are (5y - 7) and ()

You have the following expression given in the problem above, which is a quadratic equation:

5y^2 - 2y - 7=0

When you factor the quadratic equation, you obtain the following form of it:

(5y - 7) (y + 1) = 0

Therefore, as you can see the answer is: (5y - 7) (y + 1) = 0