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14 May, 13:55

Let the random variable x be equally likely to assume any of the values 1/11, 2/11, or 3/11. determine the mean and variance of x.

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  1. 14 May, 16:00
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    Mean of x = (1/11 + 2/11 + 3/11) / 3 = 6/11 / 3 = 2/11

    variance

    1/11 - 2/11 = - 1/11; 2/11 - 2/11 = 0; 3/11 - 2/11 = 1/11

    (-1/11) ^2 = 1/121, 0^2 = 0, (1/11) ^2 = 1/121

    1/121 + 0 + 1/121 = 2/121

    Variance = 1/121 / 3 = 1 / 363
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