How does the mean absolute deviation (mad) of the data in set 2 compare to the mean absolute deviation of the data in set 1? set 1: 16, 15, 10, 12 set 2: 16, 62, 15, 10, 12 the mad of set 2 is 10 less than the mad of set 1. the mad of set 2 is 13.35 more than the mad of set 1. the mad of set 2 is 10 more than the mad of set 1. the mad of set 2 is 13.35 less than the mad of set 1.

Mean absolute deviation is the average distance of the data from the mean.

Set 1

Mean = [16+15+10+12]/4 = 53/4 = 13.25

Distances of each data from the mean

|16 - 13.25| = 2.75

|15-13.25| = 1.75

|10-13.25| = 3.25

|12-13.25| = 1.25

Mean of those distances = [2.75 + 1.75 + 3.25 + 1.25]/4 = 9/4 = 2.25

Set 2

Mean = [16 + 62 + 15 + 10 + 12]/5 = 115/5 = 23

Distances of each data from the mean

|16 - 23| = 7

|62-23| = 39

|15-23| = 8

|10-23| = 13

|12-23| = 11

Mean of those distances = [7+39+8+13+11]/5 = 15.6

MAD of data set 2 - MAD of data set 1 = 15.6 - 2.25 = 13.35

Answer:The mad of set 2 is 13.35 more than the mad of set 1.