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21 October, 17:44

If a sequence is defined recursively by f (0) = 2 and

f (n + 1) = - 2f (n) + 3 for n ≥ 0, then f (2) is equal to

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  1. 21 October, 20:11
    0
    If you would like to know how much is f (2), you can calculate this using the following steps:

    f (0) = 2

    f (n+1) = - 2 * f (n) + 3

    f (1) = - 2 * f (0) + 3 = - 2 * 2 + 3 = - 4 + 3 = - 1

    f (2) = - 2 * f (1) + 3 = - 2 * (-1) + 3 = 2 + 3 = 5

    The correct result would be f (2) = 5.
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