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25 June, 19:38

The length of a rectangle is 7 inches more than its width. if the perimeter of the rectangle is 66 inches, find its dimensions.

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Answers (2)
  1. 25 June, 19:46
    0
    P=66

    L=7+w

    2L+2W=p

    2 (7+w) + 2w=66

    14+2w+2w=66

    4w=52

    w=13

    L=7+w

    L=7 + (13)

    L=20 & w=13
  2. 25 June, 23:04
    0
    Perimeter = 2 times the width + 2 times the length

    = 2 (w + 7) + 2w where w = width

    2 (w + 7) + 2w = 66

    4w + 14 = 66

    4w = 66-14 = 52

    w = 52/4 = 13

    length = 13 + 7 = 20

    width = 13 and length = 20
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