Lindsey needs a jeweler to repair her earrings. Jeweler A is offering her services for an initial $150 in addition to $14 per hour. Jeweler B is offering his services for an initial $166 in addition to $12 per hour. When will the two jewelers charge the same amount of money?

A (X) = charge offered by jeweler A

x=number of hours.

A (x) = 14x+150

B (x) = charge offered by jeweler B.

x=number of hours.

B (x) = 12x+166

When the tow jewelers charge the same amount of money A (x) will be equal to B (x);

A (x) = B (x)

Therefore, we equalize both equations and solve them.

14x+150=12x+166

14x-12x=166-150

2x=16

x=16/2

x=8

Answer:jewelers'charge would be the same when they work 8 hours.