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20 October, 16:56

What substitution should be used to rewrite 6 (x + 5) 2 + 5 (x + 5) - 4 = 0 as a quadratic equation? u = (x + 5) u = (x - 5) u = (x + 5) 2 u = (x - 5) 2

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  1. 20 October, 18:29
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    6 (x+5) ² + 5 (x+5) - 4 = 0

    (x+5) (x+5) = x (x+5) + 5 (x+5) = x² + 5x + 5x + 25 = x² + 10x + 25

    6 (x²+10x+25) + 5 (x+5) - 4 = 0

    6x² + 60x + 150 + 5x + 25 - 4 = 0

    6x² + 60x + 5x + 150 + 25 - 4 = 0

    6x² + 65x + 171 = 0

    u = (x + 5)
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