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10 January, 18:29

What are the intercepts of 7x+2y-14z=56

A. (8,0,0) (0,-28,0) (0,0,-4)

B. (8,0,0) (0,28,0) (0,0,-4)

C. (8,0,0) (0,28,0) (0,0,4)

D. (8,0,0) (0,-28,0) (0,0,4)

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Answers (1)
  1. 10 January, 21:39
    0
    Since the equation is in 3 variables, there will be 3 intercepts:

    1) x-intercept

    Where y and z coordinate are zero.

    So, we can say

    7x + 2 (0) - 14 (0) = 56

    So, x = 8 is the x-intercept

    2) y-intercept

    where x and z coordinate are zero

    So, we can write

    7 (0) + 2y - 14 (0) = 56

    So, y = 28 is the y-intercept

    3) z-intercept

    where x and y coordinates are zero

    So, we can write

    7 (0) + 2 (0) - 14z=56

    So, z=-4 is the z intercept

    Therefore, the correct answer to this question is option B
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