The hypotenuse of a right triangle is 13 cm. one of the legs is 7 cm longer than the other leg. find the area of the triangle.

Let one side be=x, the longer side = x+7use pythagoras theoremH^2=b^2+h^2169=x^2 + (x+7) ^2169=2x^2+14x+490=2x^2+14x-1200 = (2x-10) (x+12) x=5 or - 12, since it is length x=5 the longer side=5+7=12confirmation169=144+25