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15 January, 06:51

What is the sum of the finite arithmetic series 4+8+12+16 ... + 76

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  1. 15 January, 08:55
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    A (n) = 4+4 (n-1)

    a (n) = 4+4n-4

    a (n) = 4n

    76=4n

    n=19

    The sum of any arithmetic sequence (series are infinite) is:

    (a+a (n)) (n/2)

    The average of the first and last terms times the number of terms, in this case we found that n=19 so:

    19 (4+76) / 2=760
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