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Mathematics
Caiden
12 April, 19:55
X^2-4x-5=0 na formula de bhaskara
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Darryl Lucas
12 April, 23:36
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Solve for x over the real numbers:
x^2 - 4 x - 5 = 0
The left hand side factors into a product with two terms:
(x - 5) (x + 1) = 0
Split into two equations:
x - 5 = 0 or x + 1 = 0
Add 5 to both sides:
x = 5 or x + 1 = 0
Subtract 1 from both sides:
Answer: x = 5 or x = - 1
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