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17 March, 17:56

Determine f' (2) for f (x) = (x^2 - 2x) (3x-1)

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  1. 17 March, 20:10
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    f (x) = (x^2 - 2x) (3x-1) is a product and is most easily differentiated using the product rule:

    f ' (x) = (x^2 - 2x) (3) + (3x-1) (2x-2)

    Now subst. 2 for x in this equation. We get:

    f ' (2) = (2^2 - 2 (2)) * 3 + (3 (2) - 1) (2 (2) - 2), or

    =3 (4-4) + (6-1) (2) so f ' (2) = 10 (answer)
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