Find three consecutive integers that have an average of 53

Consecutive intergers are 1 away from each other so

numbers are

x, x+1, x+2

average is found by adding the numbers up and dividng the total by the number of numbers you have

so we add x+x+1+x+2 up and divide it by 3 (3 numbers)

x+x+1+x+2=x+x+x+1+2=3x+3

(3x+3) / 3=53

[3 (1x+1) ]/3=53

3/3 times 1x+1=52

1x+1=53

subtract 1 from both sides

x=52

subsitute

x+1 is the second

x+2 is the third

x+1=52+1=53

x+2=52+2=54

numbers are 52,53,54