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6 July, 14:46

I have a triangular garden such that the largest side is 6 ft less than twice the smallest and medium side is 5 ft larger than the smallest side. If the total perimeter of the garden is 47 ft, what are the lengths of the three sides

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  1. 6 July, 17:32
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    Given:

    Triangular garden

    smallest side: x

    medium side: x + 5ft

    largest side: 2x - 6ft

    Perimeter: 47 ft.

    Perimeter = smallest side + medium side + largest side

    47 ft = x + x + 5ft + 2x - 6ft

    47 ft - 5ft + 6ft = 4x

    48ft = 4x

    48ft / 4 = 4x / 4

    12 ft = x

    smallest side: x = 12 feet

    medium side: x + 5ft = 12ft + 5ft = 17 ft

    largest side: 2x - 6ft = 2 (12ft) - 6ft = 24ft - 6ft = 18ft

    Perimeter: smallest + medium + largest

    47ft = 12ft + 17ft + 18ft

    47ft = 47ft
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